Iterations
File Name: iterations.py
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59# python module.py data_types/numeric/integer/iterations.py # python -m data_types.numeric/integer data_types/numeric/integer/iterations.py import data_types.commonUtils as utils utils.print_h1('Integer Iterations') utils.print_blockquote([ 'Types are short, long, int32, int64', 'Binary, Octal, and Hexadecimal Integers', 'Underscores in Numeric Literals (Python 3.6+) ex: large_num = 1_000_000' ]) salary = 9000 increment = 500 print('\n >>>> Iterate using for loop with type casting') print(' >>>> Follow this approach on demand and Its not recommended') for text in str(salary): print(text) # print('\n >>>> Iterate using while loop') # def iterateInteger(integer_number): # stack = [] # while integer_number > 0: # digit = integer_number % 10 # stack.append(digit) # integer_number //= 10 # while stack: # print(stack.pop()) # iterateInteger(salary) # def iterateInteger(integer_number): # stack = [] # while integer_number > 0: # digit = integer_number % 10 # stack.append(digit) # integer_number //= 10 # while stack: # print(stack.pop()) def find_digit_position(number, digit_to_find): original_number = number position = 1 while number >= 10: if number % 10 == digit_to_find: return len(str(original_number)) - position + 1 number //= 10 position += 1 # Check the last digit return 1 if number == digit_to_find else -1 # Test the function with the number 9000 and digit 9 find_digit_position_number = 8778890942 find_number = 0 print(f'Position of {find_number} from {find_digit_position_number} is ', find_digit_position(find_digit_position_number, find_number))