File Name: a_basics.py ```python

Basic Statement

from stylepy import h1, h2, h3, h4, h5, h6

h1('\n # Basic Example')

Print Statement without parenthesis.

h2('\n >>>> Print Statement without parenthesis throws SyntaxError')

SyntaxError: Missing parentheses in call to 'print'. Did you mean print(...)?

print "Concatenation with variable"

Print Statement

h3('\n >>>> Print Statement ') h6('hello venkat, welcome to python')

Print Statement support comma separated arguments.

h4('\n >>>> Print Statement support n number of comma separated arguments.')

Maximum number of parameters you can pass to a function like print()

It is primarily limited by the amount of memory available on your system.

h4('hello venkat,', 'welcome to ', 'python')

Concatenation

h5('\n >>>> Print Statement Simple Concatenation') h6('hello venkat, welcome to python' + '3')

Concatenation with int variable

h6('\n >>>> Concatenation with int variable and string throws TypeError') version = 3

Your will get TypeError: unsupported operand type(s) for +: 'int' and 'str'

print(version + 'hello venkat, welcome to python')

Your will get TypeError: can only concatenate str (not "int") to str.

print('hello venkat, welcome to python' + version)

h5('\n >>>> Concatenation of int variable and string Issue fix should be with str() function')

Fix is below.

h6('hello venkat, welcome to python' + str(version))

Concatenation with string variable

h5('\n >>>> Concatenation with string variable') version = '3' print('hello venkat, welcome to python' + version)

Concatenation with string variable wrapped in String literal.

h5('\n >>>> String variable wrapped in String literal.') version = '3' h6(f"hello venkat, welcome to python{version}")

Simple Hello World Function throws IndentationError when function body statement with zero indentation.

h5('\n >>>> Simple Hello World Function throws IndentationError when function body statement with zero indentation.') h6(' >>>> Fix is 4 tabs after def statement') def helloWorld():

You will get IndentationError: expected an indented block after function definition on line 47

In Python, the execution order is typically from top to bottom, line by line.

Python first compiles your code into bytecode before it executes it. During the compilation phase, it checks for syntax errors.

if there is an IndentationError during compilation anywhere in your code, Python will not execute any part of the script because the error is caught during the compilation phase.

print('\nHello World from helloWorld()')

h5('\nHello World from helloWorld()')

Calling the function

helloWorld()

fruits = 'Apple'

h4('\nReversing fruit value using slicing') h6(fruits[::-1])```